Optimal. Leaf size=294 \[ \frac{2 F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \left (a^3 (5 A+7 C)+21 a^2 b B+21 a b^2 (A+3 C)+21 b^3 B\right )}{21 d}-\frac{2 E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \left (3 a^2 b (3 A+5 C)+3 a^3 B+15 a b^2 B+5 b^3 (A-C)\right )}{5 d}+\frac{2 a \sin (c+d x) \left (5 a^2 (5 A+7 C)+63 a b B+24 A b^2\right )}{105 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{2 \sin (c+d x) \left (21 a^2 b (3 A+5 C)+21 a^3 B+98 a b^2 B+24 A b^3\right )}{35 d \sqrt{\cos (c+d x)}}+\frac{2 (7 a B+6 A b) \sin (c+d x) (a+b \cos (c+d x))^2}{35 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 A \sin (c+d x) (a+b \cos (c+d x))^3}{7 d \cos ^{\frac{7}{2}}(c+d x)} \]
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Rubi [A] time = 0.851041, antiderivative size = 294, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 43, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.14, Rules used = {3047, 3031, 3021, 2748, 2641, 2639} \[ \frac{2 F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \left (a^3 (5 A+7 C)+21 a^2 b B+21 a b^2 (A+3 C)+21 b^3 B\right )}{21 d}-\frac{2 E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \left (3 a^2 b (3 A+5 C)+3 a^3 B+15 a b^2 B+5 b^3 (A-C)\right )}{5 d}+\frac{2 a \sin (c+d x) \left (5 a^2 (5 A+7 C)+63 a b B+24 A b^2\right )}{105 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{2 \sin (c+d x) \left (21 a^2 b (3 A+5 C)+21 a^3 B+98 a b^2 B+24 A b^3\right )}{35 d \sqrt{\cos (c+d x)}}+\frac{2 (7 a B+6 A b) \sin (c+d x) (a+b \cos (c+d x))^2}{35 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 A \sin (c+d x) (a+b \cos (c+d x))^3}{7 d \cos ^{\frac{7}{2}}(c+d x)} \]
Antiderivative was successfully verified.
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Rule 3047
Rule 3031
Rule 3021
Rule 2748
Rule 2641
Rule 2639
Rubi steps
\begin{align*} \int \frac{(a+b \cos (c+d x))^3 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right )}{\cos ^{\frac{9}{2}}(c+d x)} \, dx &=\frac{2 A (a+b \cos (c+d x))^3 \sin (c+d x)}{7 d \cos ^{\frac{7}{2}}(c+d x)}+\frac{2}{7} \int \frac{(a+b \cos (c+d x))^2 \left (\frac{1}{2} (6 A b+7 a B)+\frac{1}{2} (5 a A+7 b B+7 a C) \cos (c+d x)-\frac{1}{2} b (A-7 C) \cos ^2(c+d x)\right )}{\cos ^{\frac{7}{2}}(c+d x)} \, dx\\ &=\frac{2 (6 A b+7 a B) (a+b \cos (c+d x))^2 \sin (c+d x)}{35 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^3 \sin (c+d x)}{7 d \cos ^{\frac{7}{2}}(c+d x)}+\frac{4}{35} \int \frac{(a+b \cos (c+d x)) \left (\frac{1}{4} \left (24 A b^2+63 a b B+5 a^2 (5 A+7 C)\right )+\frac{1}{4} \left (38 a A b+21 a^2 B+35 b^2 B+70 a b C\right ) \cos (c+d x)-\frac{1}{4} b (11 A b+7 a B-35 b C) \cos ^2(c+d x)\right )}{\cos ^{\frac{5}{2}}(c+d x)} \, dx\\ &=\frac{2 a \left (24 A b^2+63 a b B+5 a^2 (5 A+7 C)\right ) \sin (c+d x)}{105 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{2 (6 A b+7 a B) (a+b \cos (c+d x))^2 \sin (c+d x)}{35 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^3 \sin (c+d x)}{7 d \cos ^{\frac{7}{2}}(c+d x)}-\frac{8}{105} \int \frac{-\frac{3}{8} \left (24 A b^3+21 a^3 B+98 a b^2 B+21 a^2 b (3 A+5 C)\right )-\frac{5}{8} \left (21 a^2 b B+21 b^3 B+21 a b^2 (A+3 C)+a^3 (5 A+7 C)\right ) \cos (c+d x)+\frac{3}{8} b^2 (11 A b+7 a B-35 b C) \cos ^2(c+d x)}{\cos ^{\frac{3}{2}}(c+d x)} \, dx\\ &=\frac{2 a \left (24 A b^2+63 a b B+5 a^2 (5 A+7 C)\right ) \sin (c+d x)}{105 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{2 \left (24 A b^3+21 a^3 B+98 a b^2 B+21 a^2 b (3 A+5 C)\right ) \sin (c+d x)}{35 d \sqrt{\cos (c+d x)}}+\frac{2 (6 A b+7 a B) (a+b \cos (c+d x))^2 \sin (c+d x)}{35 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^3 \sin (c+d x)}{7 d \cos ^{\frac{7}{2}}(c+d x)}-\frac{16}{105} \int \frac{-\frac{5}{16} \left (21 a^2 b B+21 b^3 B+21 a b^2 (A+3 C)+a^3 (5 A+7 C)\right )+\frac{21}{16} \left (3 a^3 B+15 a b^2 B+5 b^3 (A-C)+3 a^2 b (3 A+5 C)\right ) \cos (c+d x)}{\sqrt{\cos (c+d x)}} \, dx\\ &=\frac{2 a \left (24 A b^2+63 a b B+5 a^2 (5 A+7 C)\right ) \sin (c+d x)}{105 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{2 \left (24 A b^3+21 a^3 B+98 a b^2 B+21 a^2 b (3 A+5 C)\right ) \sin (c+d x)}{35 d \sqrt{\cos (c+d x)}}+\frac{2 (6 A b+7 a B) (a+b \cos (c+d x))^2 \sin (c+d x)}{35 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^3 \sin (c+d x)}{7 d \cos ^{\frac{7}{2}}(c+d x)}-\frac{1}{5} \left (3 a^3 B+15 a b^2 B+5 b^3 (A-C)+3 a^2 b (3 A+5 C)\right ) \int \sqrt{\cos (c+d x)} \, dx-\frac{1}{21} \left (-21 a^2 b B-21 b^3 B-21 a b^2 (A+3 C)-a^3 (5 A+7 C)\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx\\ &=-\frac{2 \left (3 a^3 B+15 a b^2 B+5 b^3 (A-C)+3 a^2 b (3 A+5 C)\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 d}+\frac{2 \left (21 a^2 b B+21 b^3 B+21 a b^2 (A+3 C)+a^3 (5 A+7 C)\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{21 d}+\frac{2 a \left (24 A b^2+63 a b B+5 a^2 (5 A+7 C)\right ) \sin (c+d x)}{105 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{2 \left (24 A b^3+21 a^3 B+98 a b^2 B+21 a^2 b (3 A+5 C)\right ) \sin (c+d x)}{35 d \sqrt{\cos (c+d x)}}+\frac{2 (6 A b+7 a B) (a+b \cos (c+d x))^2 \sin (c+d x)}{35 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^3 \sin (c+d x)}{7 d \cos ^{\frac{7}{2}}(c+d x)}\\ \end{align*}
Mathematica [A] time = 4.86745, size = 251, normalized size = 0.85 \[ \frac{2 \left (5 F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \left (a^3 (5 A+7 C)+21 a^2 b B+21 a b^2 (A+3 C)+21 b^3 B\right )-21 E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \left (3 a^2 b (3 A+5 C)+3 a^3 B+15 a b^2 B+5 b^3 (A-C)\right )+\frac{5 a \sin (c+d x) \left (a^2 (5 A+7 C)+21 a b B+21 A b^2\right )}{\cos ^{\frac{3}{2}}(c+d x)}+\frac{21 \sin (c+d x) \left (3 a^2 b (3 A+5 C)+3 a^3 B+15 a b^2 B+5 A b^3\right )}{\sqrt{\cos (c+d x)}}+\frac{21 a^2 (a B+3 A b) \sin (c+d x)}{\cos ^{\frac{5}{2}}(c+d x)}+\frac{15 a^3 A \sin (c+d x)}{\cos ^{\frac{7}{2}}(c+d x)}\right )}{105 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 4.113, size = 1205, normalized size = 4.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )}{\left (b \cos \left (d x + c\right ) + a\right )}^{3}}{\cos \left (d x + c\right )^{\frac{9}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{C b^{3} \cos \left (d x + c\right )^{5} +{\left (3 \, C a b^{2} + B b^{3}\right )} \cos \left (d x + c\right )^{4} + A a^{3} +{\left (3 \, C a^{2} b + 3 \, B a b^{2} + A b^{3}\right )} \cos \left (d x + c\right )^{3} +{\left (C a^{3} + 3 \, B a^{2} b + 3 \, A a b^{2}\right )} \cos \left (d x + c\right )^{2} +{\left (B a^{3} + 3 \, A a^{2} b\right )} \cos \left (d x + c\right )}{\cos \left (d x + c\right )^{\frac{9}{2}}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )}{\left (b \cos \left (d x + c\right ) + a\right )}^{3}}{\cos \left (d x + c\right )^{\frac{9}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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